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Brian Cabrera_Statistics_hw_4

# Brian Cabrera_Statistics_hw_4 - Median Q3 C2 500 0 0.1920...

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Brian Cabrera Statistics, Fall 2011 Homework 4 1) a. Yes, it is a measure of 2 possible outcomes (x) a (n) number of trials. b. 0.17886305056988 c. 0.41637082944781 d. X at least 5; at a probability of 0.762492221122399 e. Expected value among next 20 customers: 6 Standard deviation: 2.0493 2) 3) a. 0.0228; 0.0013 b. Nan, nan c. 4) a. There are 96 out of 500 observations that had exactly 12 successes. 96/500 = 0.192 And the binomial distribution came out to be 0.18. b. There were 20 trials each in the 500 observations and the calculation was taken of how many of the 500 trials had exactly 12 successes. Using a random binomial distribution, this number was 96 out of 500. Looking at a table the table gives a value of 0.584 for a k value of 12, n value of 20, and p value of 0.20. c. Descriptive Statistics: C1 Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 C1 500 0 12.120 0.0970 2.170 6.000 11.000 12.000 14.000 Variable Maximum C1 18.000

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Descriptive Statistics: C2 (Binomial) Variable N N* Mean SE Mean StDev Minimum Q1
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Unformatted text preview: Median Q3 C2 500 0 0.1920 0.0176 0.3943 0.0000 0.0000 0.0000 0.0000 Variable Maximum C2 1.0000 d. The count was 96/500 which gave 0.192. The mean of the binomial was 0.192. This two numbers should be the same, which they are. 5) a. 12.0 9.6 7.2 4.8 2.4 100 80 60 40 20 C1 Frequency Histogram of C1 Not normal distribution because it is not symmetric with a bell shaped curve and does not have a single peak like all other normal distributions. b. 27 out of 500 numbers were less than or equal to 14 and greater than or equal to 10. c. 2.4 1.6 0.8 0.0-0.8-1.6-2.4 100 80 60 40 20 C3 Frequency Histogram of C3 Descriptive Statistics: C3 Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 C3 500 0 0.0000 0.0447 1.0000 -2.3217 -0.9430 -0.0239 0.8952 Variable Maximum C3 2.7335 It is not quite a normal distribution although it is more so than the graph in 5a. d. The binomial table gives a value of 0.416 for an n value of 20, k value of 5, and p value of 0.30....
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