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Chemistry 112 Exam 2 1997

Chemistry 112 Exam 2 1997 - r emails I SECOND metros...

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Unformatted text preview: r -' emails I SECOND metros - ._ i'vlarch21.199'i' strata}: in both yen name and 11mm en the somou sheet its proper, eentptete identification? There is:~ only one BEST answer for each question The back of your periodic chart lus several constants and SR? values necessary for answering some questions. The Nernst equation is given at'the eiid of this errant. _-- The ovo questions which follow refer to the thrl'llydberg equation for-«hydrogen radiation lines: E = 2.1?33 x Ifl-l‘a ”photon . _. _ _ . firéfit _fi _ . _ -. U - “its: new s it“ _. - Calwlate the comet stole photon offight emitted whenh .. .--. ...nr- u -1eetten transition from level. '_ n=2ten=L (11 2.1?33x10‘13] {2}5.4sssttto-Ivr._r-.-gr;63ttffi._x1EH*J (4)2.7225xlil-131 (5} 21K] _ -- - : I; . _ . If one wished to use the BolalRydberg equation above to calculate milenergy necessary to ioniae an electron front the first (n=l} hydrogen orbit what value olefin] vvooldyon t-it to use? "" “l”. {Ellis-l fili- . _ .. e.- . 'Chhasthssmflflwt ensrsvperrnotenv .-_-.2 [1} visi lclight {2} X—rays-- @ Jfiifiaqedmafim“ - '- . .'_ -.-.‘- IH: . --__..__ _ ._ .._._._. 2% (awesome? -. ".'u'.. M. _ I - (2} 2 [3} a FEE) to :5 - _ t . _. "‘ What is the average oxidation nnntttet erote'ntnngentnsteeaee-ten Hf? . N2; ' - Le ' ' = =tt dstate conditions. wlettisthe'voit'age output oftbe 1331.12fo {2} 1291'! [3} 2.51 V {4) 5.49V {5} 13.931! "— Pllflgtg), 1 almlH+[x thtH+(t.osn|He(s}.l hth I}! (2) ‘i' ll.) 9 {4} ll] (5} 3.54 ' diom metal was plated onto an electrode from an aqueous solution containing Rh cations for L5 hours with acurrent of [liltififl amperes. in this time 111248 grams of Rh was deposited on the electrode. What was %w many quanortn numbers mieneoessary locompletelytdefine '- . tot tat—1 tho-(5)4 am 6m chefiiical epeete re the Ii tinting agent in ' ehnneen residue in the mummy _e'l the ob ”go on the rhodium cation in the solution? “yon/K (2} +2 El] (4) e4 i5].+.5 . - _. t what electrn the rhodium in #9 above have been deposited? r seine tent-i. = -- Wiley is constructed- based on the following chemical ritection: ‘j rem . Mn04— + a PP + 5 Ag .__-settle + 4 those. -5Ag':,'§;;1"- ' . 'I‘he eeneennnttnn cell below has n potential erosse. v at are. What is the intestine nnttnnwn H+ solption'l 2041*!) - {3] H20 } (313%an {5} 12(5} (so beat the anode Srcalhode so can'ltell wrotnntntntelnrntmnsen'ingj; .- ' liteoxidation n1 mnetnrtheenttntin fllesuifaleion? "’a- g (:3 ' @wt .(3 +2 (eh—2 [st-s rte—X— ? . _ t .. is the ice- 11 any of light that has a wavelength of 432 not? [Nestle 1o1 e! latest 1: 105 nn—t ts} 8.393(113'15'] (‘42 4.32): tostn (sq 4.32s ill-7:114 =. wavelentltof432 not? . Whatisliaeerrcrgyofa photdh ofiighlli] . _ {1} 1.253: 10431 (2) 3.31 x 10-191 __éi Minx ill-‘91 [4) 6.9411014] (5) 432] /§) 5 £1: Wm‘mun— «.__. ._.__, .. ,,,,,,,, , ,,,,,,,, ,n,!7,7,,7 , , 5,5. ., . eeaoezs Using appropriate Md man potentlals, calculate the” equilibrium eonsuint at EST: for the reaction 4;" " below: ' ' ' ' - AuWaq) +.. 4Cl1aq}. its $110] ' ' sell-""- - :1' $1321.23 mlgxtm._-.[m 'fit.t5x1me(5} seine-11 . .t.. ficmmflate itie potentinlofflieeefl below a 2511'- ’ 2112*(DGIHM) u enemies} I Cu 21.: “‘1. . -. :fl antes (sitters? (4} nos (_5_)__;. 11th meeisequstie ‘-"'i'--- -- . . [2} no- (3}i1E' {4} currentxtinie (SJ it depends Dnthelaattery mm .‘ -' which efthefollowing compounds wouldh - igen seanoxitlanonnumherof 1? ' . I I fig; {2} H20 {3} NH". n neverhn‘veanendahon numher ersi _ 1 hymflgcfl a m: - - I . . I I _ - . I . I . -_ ,c, i:.:.: (lln- «12%? (filml Him, (5):]; ' " _' - _-' " ' 24. Witch of the following quantum numbers gives the roost iuionnation about the energy. level of an orbital in a h ogen atom: " (231 Glmi (41m:s ole ' . _ -III'II'}' is at equilibrium its will 25. law that there are limits to the accuracy with which both the position and momentum of a particle can be - ' measured is due to: ' ' fistszeew r2} senieoingerrsi Planck (4) Einstein . law that the energy of a ihoton of light' is directlyr proportional to its frequency' is due to: _ __(1) tie ' {2} Sehroclingerh I4) Einstein {5} Heisenberg '- - a metal M”, a current of 1.5 srnperes flowing for one hour resulted in electrochemical messiah Haj-‘1'}.- -- I i' . : i metal from which cation in solution? - - “s:- - - ' Isos: (2} Fe” [3] Wit2 (4) Cr+6 (5] Rh+3 -. . . - E. [n which of the following is electric current from an external source userl to force a non—spontaneous chemical - ' reaction to occur: a?) oeivsnie cell (3) Half cell- (4} Pyrometeliurgical cell 4;“ (5] Smelter cell ‘9 n e <0 . . PAGE 3 ' 1':-.:-:-:;:.~.:. reflux monhglow IS balfinoqd with what is the coefficient of the 4’3- GTE: 'i‘heremontakesplaccinhmmluflon. .515.- (5)~::—_---§_-fi-'P1I3[g) -t'-"- Wag} .. . .. ,1 (2)1 I3}?! (4-1-4 (5} I? . 11th::reduxmacfiunbefiwisbalancedmmnummumimegetmeflidems what tsflmcocfi'cmnt of the NOTE: "I'ttcrcacfion placemmyfluflun. - 3- fix- “In .CIgO-fi‘taq) + Hm) {I ' fiwCfiftan + _sl :.' (DI Blimmdt (5)12 28:" I . I'n' TURN 1N SCANTIIDN SHEETS ONLY mu mi? KEEP YOUR Manon PAPERS " " I A KEY TO THIS EXAM W111. BE PbSTEIJ III THE IDBBY OF THE SCIENCE BUILDING A'I' TI-IE . - _ . _ u- . - - . . i M r2 Vic; / I} SECOND examwnnota ' July 21. 199’? Enhhlfl in both your name and W on the SCANTRUN sheet for proper, complete identification. There is onlyr one BEST answer for each question. The back of your periodic chart has several constants and SRP values nesionssanir for answering some questions. Several equations which might prove useful for some questions are given at the end of this exam. acti n is found to have a rate constant of lflfl s—1. What is the half-life of this reaction? @593»: (3}I}.1tlfls {4) cases m w r these since half-life' 1s not defined for this type of reaction 2. A catalyst for a chemical reaction affects the values of all of these except _ _ (1) activation energy [2} forward rate constant {3} reverse rate constant @equilihrium constant [5} a catalyst changes each of the previous four values Experiments Hflrmed to follow the kinetics of the reaction: 510321311} 131} —'-‘* 2 Sikkim} + E31311]. From the experimental data tabulated below, answer the following 4 questions Expt. [Sgng'tfaqfl [l'ran] Initial rate of appearance 01:13— [in moUL s) l tlflllti “dill-l4 2.2 X iii"i 2 onto Dill? 1.1 X it)" a not ~ ooa4 an X 1o4 reme 4] I 4 i124 iliil"! 3.3 X lili—4 I _ . _ _' _l 3. What is the order of the reaction widt respect to 3203115111}? (1) a Q t {a} 2 {4} s [5} more information is needed to determine this quantity 4. What is the reaction order with respect to l—taql'? {1} i} @l {El} 2 (4} 3 (5) more inforrnationis needed to determine this ottarttit},r j, ail-Ila "M Elli: i" 5. What is the rate constant for the reaction“?I — .31.. 5E \ (l) 1.1 X lD'SUrnol s 8.1311104 Limoi s {3} 8.1 Kill-1 3'" 2?, 1I' X it) (4) tot moLI'Ls t5) 1: 1x to1 Lvmetts . e. What is the initial rate of disappearance of 1—1:an in mth s when [SEOEEhifiqfl is llflfiil M and the [I‘taql] is {1' C”? M? H10 II (1)1.1x1o-4 Fgaaxnfl (3)2.2XlD-4 (4)6.6X1iJ-4 (st—1.1xto-4 - ,. i. . 5 I -’ T. In which of the following rate laws would the RATE have units of Inoh'L time? i (1:1 RATE = it no sate = that] (a) RATE = on]: on nets = tint-t i: Q on ants wet-1e have these units in all oftlte shove i155 " 3. [n which of the following rate laws woul e rate constant have units of Urnoi time? H; -. (1} RATE = k [2} RATE 2 lr[A1 ATE = km]? {4} RATE = HAP 'qj "k [5} the rate constant would have mess u in all of the above 9. For a general first order reaction, a —:=- pl'ilduL'tS. with a rate constant of till] i] s'1 and an initial concentration of Aof ill M, how long wi ' take for the concentration of a to fall to 1.3 M? [1} 159.3 s {2] illlil] s {3} lilil s 4);.43 s {5} "iii s M'_.-’ til. in which of the followin nitrogen have an oxidation number of +3? (1] N10 {2) NO .43] N2 (5} N305 "=- __|,_‘- _ z . if: ur ow '1-1 — PAGE 2 - 11. When the following redo: reaction is balanced using minimal integral coefficients, the coefficient for ‘12 is ? . "the reaction takes place in basic solution. I: __:. I-(an + Mean) (1)1 (212 @1415 {516 [2. The reaction below taltes place in acidic solution. When the reaction is nt'u'roctl}r balanced with minimum integers for coefficients. the coefficient of the Fe3+ is ‘7 Fe3+ + Mao..- :- 1+ + Fe3+ “I“- 111 1 121 2 o} a - 151 6 13. ‘ . value for as“ for the tedott reaction in problem 12 above? _ l 11.112111r {a} 1.051 v {3) 4.111511.F t4} assert {5) [1.44:] v. 14. [n the reaction shown below. what chemical specie is the reducing agent? :1- 2 SUE-{sq}. + 131an 820311 'taqi {1} 52031— 2} I— {3) 504 — (4} [3— (5} electrons arethereducing agents here “' 15. Using appropriate SRP’s from your chart. calculate the son of B s . [1} 191.3 kl (2] 491.3 lei {3} 23.3 1:1 [4} 140.5 it] l:__ #5.? " 2 _—‘—-—u——"' calculate the Klip pf PbSEMs] at 2.512. 1... 16. Using appropriate SRP's from your ~ 124} 4x1o~11 [5} 3x til-9 IE1} 15 X ill—15 (2] 5 X1043 \ _.Y " .-' J12. A current of 1.25 amps is delivered for 23 min.- How man}.r ectrons passed through this circuit? 1:11 was (21 1.125 (a) 1.25 X11123 (41 11.119 - Moon ‘TL" 13. A current of 1.5 amps flowing for Lilli hour produced 2.? g of a metal, M. front a solution of its cation M2+[aq). What was the metal? {1} Ni {2} Fe Mo; (4) Rh {5] Zn 55.3 is 1113 res 19. At which new: electrochemical cell would the metal in problem 13 above have been deposited? {ii anode '} catho [3} both the anode 31. camode {4} it would depend on the sign of E' {5} more informa ‘ dad to determine the electrode 2i}. Which specie 's the st [most powerful] reducing agent under standard conditions? {1} Ba1+ 2})(la ' [3} (4i Br1 {5) Mum- 21. Which specieb is the best [most powe ‘ ‘ agent under standard conditions? (11 age _ f (sag maps: were 22. What is the oxidation number Wen in the nitrate ion? (1;. —s {a} +3 1:3} +1 [413% 23. Calculate the potential of the cell below at 25°C. 2”(tillllllllirll|| $112.01“) | Cu I} 1.17"? {2} LIUV {3} Illa-5"».F [4} {will t5}v1.lflV 24. What is the product of the anode reaction in die cell below? an 133' I Uhfl || Cu2+t2flMl | Cu (3} Cu2+ (4) Du {5} the product is not shown in the cell representation 25. The concentration cell below has a potential offl.354 V at 25°C. What is the pH of the unknown H+ solution? Pt I Hfig}. 1 attn i this M) 11 11+ (to so 1 HztgiJ aim | Ft @1221 1' (3) s (431111 {513.54 - PAGE 3 - 26. Zinc is capable of reducing if} M solutions of which of these metal ions to its corresponding metal? (2} at?” (3) Ms2+ (4) Ca1+ (5) tie2+ 2?. The lead storage battery used in automobiles is based on the following redoit reaction: Pb{s) + Pbflyjs] + 2 504 ' + 4 H+ —::r 2 FhSD4-(s1t + 2 H20 us of t'lE' for this cell? [112.1341 V (2) 41} if {3} til) 1*" (4] ill] V [5} 1.311%r 28. en autoredox reaction is a reaction in which (1} as“ is positive and therefore the reaction is spontaneous E is positive and therefore the reaction is spontaneous til ne chemical specie is both oxidized and reduced 4] as is negative and therefore the reaction is spontaneous (5} a redox rection takes place which will provide enough energyr to run an auto ’29. Platinum is often used as electrode material in cell construction because; {I} it is one of the most powerful oxidizing agents it is one of the most powerful reducing agents - it is relatively chemically inert and will not take part in redox processes but conducts current it is one of the cheapest materials available in our environment (5] platinum, in fact. is almost never used in cells 3!]. How many moles of electrons are being transferred in the lead storage battery reaction shown above in problem ‘ [l] l @ (3) 4 (4] 6 [5) 12 USEFUL FD RMULAE lt=rlt.e'EEILIIrELT or lofltll=1ntA}-fEafRT} 30' i ”:4 -- Ovolflt lad ear- be 6-? “tart-fa it?) for a first order reaction a —-:=~ products ]:l'l[r‘5L]t 2 input. a kt ”“4 + acres .: 3st res manner somehow an" arc is: are = as“ s (unease) log o A KEY TO THE EXAM WTLL BE POSTED IN THE RESOURCE ROOM FULLOWNG THE EXAM ...
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