scd_s6 - SCD - Seminarul 6 Circuite basculante monostabile....

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Unformatted text preview: SCD - Seminarul 6 Circuite basculante monostabile. Problema 1 0 = 100 U BE = 0,8V U CEsat = 0V Acest circiut are doua stari: 1. O stare stabila, in care T 2 este in saturatie si T 1 blocat, care caracterizeaza regimul stationar (de curent continuu). Condensatoarele au o tensiune constanta la borne. 2. O stare cvasistabila, in care T 1 este in saturatie si T 2 este in blocat, stare temporara si cu o durata de timp T bine determinata. Trecerea de la starea stabila la cea cvasistabila se face prin aplicarea unui impuls corespunzator de declansare intr-unul din punctele reactiei pozitive: V B1 V C1 V B2 V C2 V B1 De exemplu +-- + + Impuls crescator in baza lui T 1 In starea stabila, tranzistorul T 2 este mereu in conductie deoarece circuitul sau de alimentare si polarizare este: T 2 saturat si U C2 = V OL2 = U CEsat = 0 R C1 1K R B 10K R 2 10K R 1 10K T 1 T 2 R C2 1K C a 100pF C 10nF R b R C2 V CC T 2 I B2 2 2 2 1 C CE CC SI B B BE CC B R U V I R U V I- =- = V CC = 10V SCD - Seminarul 6...
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This note was uploaded on 11/05/2011 for the course AUTOMATIC 29 taught by Professor Eduardandrei during the Fall '11 term at UPB Colombia.

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scd_s6 - SCD - Seminarul 6 Circuite basculante monostabile....

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