MAE 101 homework 3

# MAE 101 homework 3 - B must not exceed 140 kN. Based on...

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MAE 101: Statics and Strength of Materials Fall 2011 Due Friday, October 7 th , 2011 Problem 6. (Problem 2.17 from the Gross et al.) A smooth Sphere (weight G , radius R ) rests on three points A , B and C . These three points form an equivaleteral triangle in a horizontal plane. The height of the triangle is 3 a = 3 4 3 R (see Figure). The action line of the applied force F passes through the center of the sphere. Determine the contact forces at A,B and C . Find the magnitude of the Force F required to lift the sphere off at C . Answer A = B = 2 3 ± G + 1 3 F ² , C = 2 3 ± G - 2 3 F ² A = A 4 - 3 3 2 , B = B 4 - 3 - 3 2 C = C 4 2 3 0 2 F = 3 2 G Problem 7. (Problem 5.15 from Beford et al). A structural designer determines that the magnitude of the force exerted on the support A by the beam must not exceed 80 kN, and the magnitude of the force exerted on the support

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Unformatted text preview: B must not exceed 140 kN. Based on these criteria, what is the largest allowable value of the upward load F ? Problem 8. (Problem 5.24 from Bedford et al). The 14.5-lb chain saw is subjected to the loads at A by the log it cuts. Determine the reactions R, B x and B y that must be applied by the person using the saw to hold it in equilibrium. Answer B X = 11 . 257 lb, B Y = 15 . 337 lb, R = 12 . 514 lb 1 Problem 9 (Problem 5.46 from Bedford et al). The mass of each of the suspended boxes is 80kg. Determine the reactions at the supports at A and E . Answer A X =-1570 N, A Y = 1570 N, E X = 1570 N 2...
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## This note was uploaded on 11/06/2011 for the course MAE 101 taught by Professor Orient during the Spring '08 term at UCLA.

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MAE 101 homework 3 - B must not exceed 140 kN. Based on...

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