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MAE 101 homework 5

# MAE 101 homework 5 - m that the frame will safely support...

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MAE 101: Statics and Strength of Materials Fall 2011 Due Friday, October 19 th , 2011 Problem 18 (Problem 6.8 from Bedford et al.) The Howe and Pratt bridge trusses are subjected to identical loads (a) In wich truss does the largest tensile force occur? In what member(s) does it occur and what is its value? (b) In which truss does the largest compressive force occur? In what member(s) does it occur and what is its value? Problem 19 (Problem 6.35 from Bedford et al). For the Howe and Pratt trussese, use the method of sections to determine the axial force in member BC . Answer Howe T BC = - 2 . 25 F Pratt T BC = - 3 . 5 F Problem 20 (Problem 6.46 from Bedford et al). Consider the truss shown. Use the method of sections to determine the axial force in member FG . Answer FG = - 3 . 33 kip 1

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Problem 21 (Problem 6.55 from Bedford et al). The force F = 10 kN. Determine the forces on member ABC Answer B = - D = - 8 kN C = - E = 2 kN A = 6 kN Problem 22 (Problem 6.75 from Bedford et al). The pin support at B will safely support a force of 24-kN magnitude. Based on this criterion, what is the largest mass
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Unformatted text preview: m that the frame will safely support Answer m = 2421 kg Problem 23 (Problem 6.80 from Bedford et al). The weight W = 60 kip. What is the magnitude of the force the members exert on each other at D . Answer | ~ D | = 110 kip 2 Problem 24 (Problem 6.81 from Bedford et al). The ﬁgure is a diagram of the bones and biceps muscle of a person’s arm supporting a mass. Tension in the biceps muscle holds the forearm in horizontal position as illustrated in the simple me-chanical model as shown in Fig b. The weight of the forearm is 9N and the mass m = 2 kg 1. Determine the tension in the biceps muscle AB 2. Determine the magnitude of the force exerted on the up-per arm by the forearm at the elbow joint C . Answer T AB = 166 . 76 N F C = 138 . 65 N Problem 25 (Problem 6.89 from Bedford et al). Determine the force exerted on the bold by the bolt cutters. Answer F = 1051 N 3...
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