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Unformatted text preview: ECE 329 Homework 7 Solution Due: July 8, 2011, 5PM 1. Verifying vector identity H E E H = E H for E = 2 e z x and H = 4 e z y. Solving the lefthand side of the identity gives H E E H = (4 e z y ) x y z z 2 e z (2 e z x ) x y z z 4 e z = (4 e z y ) ( 2 e z y ) (2 e z x ) (4 e z x ) = 8 e 2 z 8 e 2 z = 16 e 2 z and the righthand side gives E H = ( 2 e z x 4 e z y ) = ( 8 e 2 z z ) = z ( 8 e 2 z ) = 16 e 2 z , hence, the identity is verified. 2. Continuity equation. a) Taking the divergence of J = ( 4 z 2 x + 3 x 3 y y + 2 z ( y y o ) 2 z ) A / m 2 we get J = x ( 4 z 2 ) + y ( 3 x 3 y ) + z ( 2 z ( y y o ) 2 ) = 3 x 3 + 2( y y o ) 2 ....
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 Summer '08
 Kim

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