hw8_sol - seen between two terminals of C E (as discussed...

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ECE 342 HW#8 Solutions (P9.11) See next page.
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f L =f P1 +f P2 +f P3 =102.1 Hz Note that, when calculating f P2 , Re should go in parallel with the entire square bracket in equation (9.14), since is is in parallel from the viewpoint of the resistance
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Unformatted text preview: seen between two terminals of C E (as discussed below the equation 9.14). ' || 2.15 ||1 0.683 1 16.225 2 14.37 0.683 in in S H R R R k f MHz p k π = = = Ω ⇒ = = × × ( ) ( ) → R in = R i || r π =2.15k Ω...
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This note was uploaded on 11/06/2011 for the course ECE 342 taught by Professor Nareshshanbhag during the Spring '11 term at University of Illinois, Urbana Champaign.

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hw8_sol - seen between two terminals of C E (as discussed...

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