hw4soln - In Chapter 5 of the course textbook by Bergen and...

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λ 22 6.089 10 5 × V sec m = λ 22 µ 0 2 π I ln 1 21 := λ 21 5.991 10 5 × V sec m = λ 12 6.516 10 5 × V sec m = λ 11 6.438 10 5 × V sec m = λ 21 µ 0 2 π I ln 1 20 := λ 12 µ 0 2 π Iln 1 26 := λ 11 µ 0 2 π 1 25 := That's how the author's solution manual solves it. We really could use some more details. We seek the flux that links the telephone wires and electrical wires. This relates to a mutual inducance behavior, not a self inductance behavior. Therefore, we should identify the currents that cause the flux and calculate the amount of that flux that links the other lines. There will be 4 terms here, a mutual flux generated by each of two currents (going and returning) linked to each of two telephone wires. Make every effort to get the algebraic signs consistent. V t 0.116 V mi = V t 7.215 10 5 × V m = V t j ω ⋅λ := Find the voltage per unit length λ 1.914 10 7 × Wb m = λ µ 0 2 π d p d s + d t + d p d s + I () l n d s d t + d s + := Find the flux that links the telephone line. j1 := d t 1ft := d s 20 ft := d p 5ft := ω 2 π 60 rad sec := I 100 A := µ 0 4 π 10 7 henry m := State the given 5 ft 1 ft 20 ft +I - I Suppose that a 60 Hz single phase power line and an open wire telephone line are parallel to each other and in the same horizontal plane. The power line spacing is 5 feet and the telephone wire spacing is 12 inches. The nearest conductors of the two lines are 20 feet apart.
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This note was uploaded on 11/06/2011 for the course ECON 6545 taught by Professor Gully during the Spring '11 term at Temple.

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hw4soln - In Chapter 5 of the course textbook by Bergen and...

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