# BOD_2 - water • X = mL of seeded dilution water • Y =...

This preview shows pages 1–7. Sign up to view the full content.

How to compute for BOD

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
BOD = I F (undiluted) Where: I = initial dissolved oxygen F = final dissolved oxygen BOD = (I F)/(dilution) (diluted)
Test sample A BOD 5 = 8 2 BOD 5 = 6 mg/L How about test sample B?

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Test sample B BOD 5 = 8 0 BOD 5 = 8 mg/L DILUTE. Add 1/10 dilution
Test sample C BOD 5 = (8 4)/(1/10) BOD 5 = 40 mg/L

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
BOD (mg/L) = (I F) – (I’ - F’)(X/Y) D Where: I = initial dissolved oxygen F = final dissolved oxygen I’= initial dissolved oxygen of the seeded dilution water F’= final dissolved oxygen of the seeded dilution
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: water • X = mL of seeded dilution water • Y = total mL • D = dilution of the sample  BOD (mg/L) = (I – F) – (I’-F’)(X/Y) D  Where: • I = initial dissolved oxygen • F = final dissolved oxygen • I’= initial dissolved oxygen of the seeded dilution water • F’= final dissolved oxygen of the seeded dilution water • X = mL of seeded dilution water • Y = total mL • D = dilution of the sample...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern