BOD_2 - water • X = mL of seeded dilution water • Y =...

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How to compute for BOD
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BOD = I F (undiluted) Where: I = initial dissolved oxygen F = final dissolved oxygen BOD = (I F)/(dilution) (diluted)
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Test sample A BOD 5 = 8 2 BOD 5 = 6 mg/L How about test sample B?
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Test sample B BOD 5 = 8 0 BOD 5 = 8 mg/L DILUTE. Add 1/10 dilution
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Test sample C BOD 5 = (8 4)/(1/10) BOD 5 = 40 mg/L
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BOD (mg/L) = (I F) – (I’ - F’)(X/Y) D Where: I = initial dissolved oxygen F = final dissolved oxygen I’= initial dissolved oxygen of the seeded dilution water F’= final dissolved oxygen of the seeded dilution
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Unformatted text preview: water • X = mL of seeded dilution water • Y = total mL • D = dilution of the sample  BOD (mg/L) = (I – F) – (I’-F’)(X/Y) D  Where: • I = initial dissolved oxygen • F = final dissolved oxygen • I’= initial dissolved oxygen of the seeded dilution water • F’= final dissolved oxygen of the seeded dilution water • X = mL of seeded dilution water • Y = total mL • D = dilution of the sample...
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This note was uploaded on 11/07/2011 for the course ECON 1129863 taught by Professor Stewart during the Spring '11 term at ENSEA.

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BOD_2 - water • X = mL of seeded dilution water • Y =...

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