3D6 - F 1.00065878 x B = 0.002 mol fract h B = 8039.523...

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ChE 305 Problem 3 D6 H V = 15224.76 Btu/lbmole Q C D= 997.994 lbmole/hr K x i 36.13601 ° C 36.09485 ° C 1.002101 0.996905622 97.04482 ° F 3991.976 96.97074 ° F 0.316042 0.003164135 x D = 0.999 mol fract λ 1.000069757 h D = 3850.902 Btu/lbmole 11373.86 RR= 3 L= 2993.982 F= 2500 lbmole/hr L/V= 0.75 y intercept 0.24975 T F = 30 °C P= 760 mmHg q= 1.153305 K i y i Z= 0.4 mol fract 5877.243 1.000695 0.999694701 h F = 4033.4 Btu/lbmole 4375.237 0.315525 0.000315525 86 ° F 1.343297 1.000010226 T ref = 0 ° F y intercept -0.00069 2.693634 0.005387267 0.997266 0.995271513 H V = 21607.02 1.00065878 Q R K y i 68.65309 ° C B= 1502.006 lbmole/hr 2.693634 0.005387267 155.5756 ° F 68.65309 ° C 0.997266 0.995271513 155.5756
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Unformatted text preview: F 1.00065878 x B = 0.002 mol fract h B = 8039.523 Btu/lbmole 13567.5 H= 18415.89 Btu/lbmole Q C =-45404185 Btu/hr h= 5945.212 Btu/lbmole Q R = 51239273.6 Btu/hr C PL Btu/lbmole C F Btu/lbmole F a b c d MW A B C n-pentane 11369 36.07 96.926 39.7 27.45 0.08148 4.54E-05 1.01E-08 72.15 6.85221 1064.63 232 n-hexane 13572 68.74 155.732 51.7 32.85 0.09763-5.72E-05 1.38E-08 86.17 6.87776 1171.53 224.366 C PV , cal/mole C Antoine Constants Normal BP = L = V = V L...
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