patino_chm2046_chapter16

Solubility pb2 130 10 3 m 130 i i i 2

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Unformatted text preview: gCl is solid AgCl = (1.67 x 10-5)(1.67 x 10-5) = (1.67 x 10-5)2 = 2.79 x 10-10 Ksp = solubility product constant Lead(II) chloride Lead(II) PbCl2(s) ⇄ Pb2+(aq) + 2 Cl-(aq) (s) (aq) Ksp = 1.9 x 10-5 = [Pb2+][Cl–]2 Silver Silver Agcarbonate CO (s) ⇄ 2Ag (aq) (s) carbonate 2 3 + + CO32-(aq) (aq) Ksp = 8.5 x 10-12 = [Ag+]2[CO32-] Ksp from solubility Consider PbI2 dissolving in water. Consider PbI2(s) ⇄ Pb2+(aq) + 2 I-(aq) (s) Calculate Ksp if the molar solubility Calculate PbI2 = 0.00130 M PbI Solution Solution 1. Solubility = [Pb2+] = 1.30 × 10-3 M 1.30 [I-] = ? [I [I-] = 2 x [Pb2+] = 2.60 × 10-3 M 2.60 Ksp = (1.30 × 10-3 )(2.60 × 10-3 )2 = 8.79 × 10-9 Ksp = solubility × (2× solubility)2 = 4 S3 Ksp from solubility Consider MgF2 dissolving in water. MgF2(s) ⇄ Mg2+(aq) + 2 F-(aq) (s) Calculate Ksp Calculate 4 if molar its solubility = 2.65 × 10--4 M solubility Solution (alternatively) Solution Ksp = [Mg2+] [F-]2 = [Mg2+] {2 • [Mg2+]}2 [Mg Ksp = 4 [Mg2+]3 = 4 (solubility)33 = 4 (solubility) Ksp = 4 ((2.65 × 10-4))33 = 7.44 × 10-11 Ksp = 4 2.65 × 10-4 = 7.44 × 10-11 Solubility from Ksp Q: Ksp of PbBr2= 6.6 × 10-6. Calculate the SOLUBILITY of the salt in mol/L & g/L. PbBr2(s) ⇄ Pb2+(aq) + 2Br-(aq) x→ x SOLUTION I C E 2x Step 1 Pb2+ 0 +x x 2Br0 +2x 2x Solubility from Ksp Q: Ksp of PbBr2= 6.6 × 10-6. Calculate the of the salt in mol/L & g/L. solubility Step 2 Substitute into Ksp expression & solving for x: Ksp = [Pb2+][Br-]2 = (x)(2x)2 = 4 x3 x=3 K sp 4 6.6 × 10 x=3 4 −6 mol = 0.012 L Solubility in g/L: 0.012 mol/L × 367 g/mol Solubility = 4.4 g/L . 4.4 Precipitating an Insoluble Salt Precipitating Hg2Cl2(s) ⇄ Hg22+(aq) + 2 Cl-(aq) (s) Ksp = 1.1 x 10-18 = [Hg22+] [Cl-]2 If [Hg22+] = 0.010 M, what [Cl-] is required to is just begin the precipitation of Hg2Cl2? just That is, what is the maximum [Cl -] that that can be in solution with 0.010 M Hg22+ can without forming Hg2Cl2(s)? without Precipitating an Insoluble Salt Precipitating Hg2Cl2(s) ⇄ Hg22+(aq) + 2 Cl-(aq) (s) Ksp = 1....
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