{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

IRWIN 9e 4_13

# IRWIN 9e 4_13 - Irwin Basic Engineering Circuit Analysis...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Irwin, Basic Engineering Circuit Analysis, 9/E 1 ._—————*—'———— 4.13 In a useful application, the ampliﬁer drivas at [03.11.1113 circuit in Pig. P4.13 models this scmariu. [a] Sketch the gain ENC; fDl' III] II 5 EL 5 on. [b] Sketch Ia for 1n [1 ER; 5 no if V; = DJ 1r. it] Repeat {h} in; = 1.0 1r. [d] 1l‘lil'hnt is the minimum value 01' R; if IIHI must be less than 100 mA for “3| *1: (1.5 V? (e) 1l‘lil'hnt is the current IS ifRL is III} II? Rapcnt for EL = mm. R2=2?lﬂ Rl=sm Figure P443 SOLUTION: Vo=l0 Chapter 4: Operational Ampliﬁers Problem 4.13 2 Irwin, Basic Engineering Circuit Analysis. 9/E ‘0 ‘9 0° /2L( 12) (b) V,=O'l\/ , v<9 =IO(o-l) : IV To: IL" I, IQ: V9 4 V0 307‘“)? RL Whoa, < < h 4— :3 ~— 0 + — 3 - A \$1 \ 0003“ 30 \ Io \ I56? I ,_> 3 3 L). O [O Io lOO —-7°° RLC'Q) Problem 4.13 Chapter 4: Operational Amplifiers ’ Irwin, Basic Engineering Circuit Analysis. 9/E 3 5 IO : [O + __LQ__/ 3mm" 2:. IolmA) I000 500 V3 “—r- w i~ ~ ~~~-~~—-~~w——~m - ——~ ~ to lOO looo “—9 00 RL (—0—) (a) V5 :O'SV ) v0: 5V Io = 5 4 _5_. 302((03 RI. 5” + 5 < 100x16S 3'oXlO3 RL (6) IS know mu m won-ihwvi'h? WM 9g W op ”amp L=O ‘. Hm vcuLwL <95 RL dwmut maﬁa. Chapter 4: Operational Ampliﬁers Problem 4.13 ...
View Full Document

{[ snackBarMessage ]}