lecture2 - 16.522 Space Propulsion Prof Manuel...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
16.522, Space Propulsion Lecture 2 Prof. Manuel Martinez-Sanchez Page 1 of 1 9 16.522, Space Propulsion Prof. Manuel Martinez-Sanchez Lecture 2: Mission Analysis for Low Thrust 1. Constant Power and Thrust: Prescribed Mission Time Starting with a mass 0 M , and operating for a time t an electric thruster of jet speed c, such as to accomplish an equivalent (force-free) velocity change of V , the final mass is dv dM M = - c dt dt dM dv = -c M if c=constant (consistent with constant power and thrust), then f M v = c ln M 0 - V c f 0 M =M e (1) and the propellant mass used V - c P 0 M =M 1- e (2) The structural mass is comprised of a part Mso which is independent of power level, plus a part P α proportional to rated power P, where α is the specific mass of the powerplant and thruster system. In turn, the power can be expressed as the rate of expenditure of jet kinetic energy, divided by the propulsive efficiency: 2 1 P = mc 2 η i (3) and, since m i is also a constant in this case, p m=M t. i Altogether, then, 2 P s so M M =M + c 2 t α η (4) The payload mass is L f s M =M -M . Combining the above expressions,
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
16.522, Space Propulsion Lecture 2 Prof. Manuel Martinez-Sanchez Page 2 of 19 ( ) 2 - V c - V c so L o o M M c = e - - 1- e M M 2 t α η (5) Stuhlinger [1] introduced a “characteristic velocity” ch 2 t v = η α (6) whose meaning, from the definition of α is that, if the powerplant mass above were to be accelerated by converting all of the electrical energy generated during t, it would then reach the velocity ch v . Since other masses are also present, ch v must clearly represent an upper limit to the achievable mission V and is in any case a convenient yardstick for both V and c. Figure 1 shows the shape of the curves of L so o M +M M versus ch c/v with ch V v as a parameter. The existence of an optimum c in each case is apparent from the figure. This optimum c is seen to be near ch v hence greater than V . If V c is taken to be a small quantity, expansion of the exponentials in (5) allows an approximate analytical expression for the optimum c: 2 OPT ch ch 1 1 V c v - V - 2 24 v (7) Figure 1 also shows that, as anticipated, the maximum V for which a positive payload can be carried (with negligible so M ) is of the order of ch 0.8 v . Even at this high V , Equation (7) is seen to still hold fairly well. To the same order of approximation, the mass breakdown for the optimum c is as shown in Figure 2. The effects of (constant) efficiency, powerplant specific mass and mission time are all lumped into the parameter ch v . Equation (7) then shows that a high specific impulse sp I = c gis indicated when the powerplant is light and/or the mission is allowed a long duration. Figure 2 then shows that, for a fixed V , these same attributes tend to give a high payload fraction and small (and comparable) structural and fuel fractions.
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern