hw solutions – chapter 5 (1)

hw solutions – chapter 5 (1) - Ax = ((F/3)...

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Homework Solutions – Chapter 5 5.1 A = 145.6 lb B = 109.4 lb 5.3 A = 33.3 lb B = 53.3 lb 5.4 A = -53.3 lbs B = 213.3 lb F = 120 lb 5.5 Cx = -5.625 N Cy = 16.5 N D = 9.375 N
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5.6 B = 42.86 N Ax = 68.57 N Ay = -51.43 N 5.8 d = 3.10 ft B = 462.5 lb 5.10 a. Dy = (F/3) + (2P/3) Ay = (2F/3) + (P/3) Ax = 0 b. D = ((F/3) + (2P/3))(2/√3) Ay = (2F/3) + (P/3)
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Unformatted text preview: Ax = ((F/3) + (2P/3))(1/3) c. Ay = F + P M D = L((F/3) + (2P/3)) Dx = 0 d. Ax = 0 Ay = F + P M A = L((F/3) + (2P/3)) 5.12 Ay = 1.884 kN Ey = 2.116 kN Ex = - 2 kN 5.13 Gx = 0 kN Gy = 3.167 kN Ay = 2.833 kN...
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This note was uploaded on 11/08/2011 for the course ENGR 111 A taught by Professor Reddy during the Spring '10 term at Texas A&M.

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hw solutions – chapter 5 (1) - Ax = ((F/3)...

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