Unformatted text preview: T CD = 2.443 kN T CE0.7783 kN T DE = 2.443 kN 6.8 T DF = 3.657 kN T CE = 3.753 kN 6.9 T AB = 3.61 kN T AC = 2.00 kN T BC = 0 kN T BD = 3.61 kN T CD = 4.00 kN T CE 0 kN T CF = 2.00 kN T DE = 3.61 kN T EF = 3.61 kN 6.10 T AB = 4.00 kN T AC = 0 kN T BC = 7.21 kN T BD = 6.00 kN T CD = 5.00 kN T CE6.00 kN T DE = 7.21 kN 6.17 By inspection: T BD = T DE = 0 T AB = T BC = P/2 T AD = (Q+(P/2))(2/√2) T EF =T CE = P/2 T DF = (Q+P)(2/√2) T CD = (P/√2)...
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 Spring '10
 Reddy
 kN, 0 lb, 500 lb, 375 lb, 625 lb

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