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# A5 - Weihan Ni A20252394 MBA 507 Decision Making Assignment...

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Weihan Ni A20252394 MBA 507 Decision Making Assignment 1 11.14 a) It’s not a random sample, but perhaps representative; less than 10% all days; more than 10 successes and failures; the 95% confidence interval : ±z*=0.56±1.96=0.56±0.062=(0.498,0.622) b) No, 0.50 is in the interval. If the market is not random, the confidence interval would not include 0.50. c) The significance level is α=0.05; it is a two-tail test based on a 95% confidence interval. 11.22 a) Let p be proportion of bills being paid by medicare. H 0 :p=0.31 H A :p0.31 b) Assume that the sample is representative of the population. 8368<10%, np=8368*0.31>10, nq=8368*0.69>10 c) SD()== = 0.00506, z= = = 1.98, P-value= 2*0.02385=0.048 d) The null hypothesis H 0 is rejeacted at . There is evidence of that p has increased. e) No, the difference is too small, not practical significant. We need look into more data. 11.28 p is the proportion of the damaged goods. H 0 :p=0.02 H A :p>0.02 np=60*0.02=1.2<10 The normal model is not appropriate for this sample distribution. Better not to proceed with a hypothesis test.

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A5 - Weihan Ni A20252394 MBA 507 Decision Making Assignment...

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