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Unformatted text preview: 39.948 = 4.31 x 10 4 cms ! 1 c mp = 2RT M = 2 8.314 x 10 7 ( ) 298 ( ) 39.948 = 3.52 x 10 4 cms ! 1 c = 8RT ! M = 8 8.314 x 10 7 ( ) 298 ( ) 39.948 ! ( ) = 3.97 x 10 4 cms " 1 5. c rms = 3RT M T = c rms ( ) 2 M 3R = 1.50 x 10 3 ms ! 1 ( ) 2 47.998 x 10 ! 3 kgmol ! 1 ( ) 3 8.314J K ! 1 mol ! 1 ( ) = 4.33 x 10 3 K Chemistry 440 Problem Set 5 – Solutions Fall 2011 Page 3 6. E trans = N 1 2 mc 2 ! " # $ % & = 3 2 NkT T = mc 2 3k = Mc 2 3R = 4.0026 ( ) 2.74 x 10 4 ( ) 2 3 8.314 x 10 7 ( ) = 12.1 K 7. ! = kT 2 1/2 " p [19] = 1.381 x 10 # 23 J K # 1 ( ) x 298.15K ( ) 2 1/2 ( ) x 0.43 x 10 # 18 m 2 ( ) x p ( ) = 6.8 x 10 # 3 m p / Pa ( ) = 6.7 x 10 # 8 m p / atm a) When p = 10 atm, λ = 6.7 x 109 m, or 6.7 nm . b) When p = 1 atm, λ = 67 nm. c) When p = 106 atm, λ = 6.7 cm . The mean free path is inversely proportional to p and to z....
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 Fall '08
 Gennis
 Chemistry, Physical chemistry, pH, Orders of magnitude, Untouchable number, Kinetic theory, Mean free path

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