IRWIN 9e 6_13

IRWIN 9e 6_13 - irwin, Basic Engineering Circuit Analysis,...

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Unformatted text preview: irwin, Basic Engineering Circuit Analysis, 9/E 1 6.13 [Haw the u-';11.'ei'nrrn fur the current in a EJFuF unpacimr when the czajmuflm' mull-age is 21:: described in Fig. P613. Figure PEA} SOLUTION: 5 60143 4 1: < 10041: \/=1i—2~5><io xv ) ct: (lug) (‘2~5Xio5) d: “SA 6 locus S i<léou§) Vr—32+ 0 tv 3 IS 2 log : c4 _. “J ”[ )3] at: I'GA Chapter 6: Capacitance and Inductance Problem 6.13 2 Irwin. Basic Engineering Circuit Analysis. 9/E Mi) = 0 i<0 MA cg J< QOHS ~2va 60“; g 1: < ’00” i-6A locusg1<leous O J 7/ ((301.1: Problem 6.13 Chapter 6: Capacitance and Inductance ...
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IRWIN 9e 6_13 - irwin, Basic Engineering Circuit Analysis,...

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