IRWIN 9e 6_15

# IRWIN 9e 6_15 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis. 9/E 1 6.15 The H-‘awct'm'm fur tho currcnt in z: SID-HF capacitm' 1's sham-'11 in Fig. Pb. [5. Determine the waveform fur the czij'lauitm' voltage. sir} {mm 10 0 1a 20 30 40 rims-J, Figure P645 SOLUTION: {<0 , L{x)=0 , V(1)=iO Oét < Moms ) 1(1) : 0251c WI) :- J. Jamar +vo C var) = _J_ 025 idt 50y ' Va) 1 9422 50/» 1 V(:t) : 7.500th i >/ MOMS , L(i)‘jo V”) .-.—. | Odi+1soo(wom)‘ —_§ 50),; v0): W Chapter 6: Capacitance and Inductance Problem 6.15 2 Inn/in. Basic Engineering Circuit Analysis. 9/E VU): O i <0 150012V 06' i < (mums qv at 9/ Moms _____________________.__—————-———— Problem 6.15 Chapter 6: Capacitance and Inductance ...
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• Fall '08
• ARAVENA
• Electrical network, Voltage drop, Basic Engineering Circuit, Basic Engineering Circuit Analysis., Engineering Circuit Analysis.

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IRWIN 9e 6_15 - Irwin Basic Engineering Circuit Analysis...

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