IRWIN 9e 6_30

# IRWIN 9e 6_30 - Irwin Basic Engineering Circuit Analysis...

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Unformatted text preview: Irwin, Basic Engineering Circuit Analysis. 9/E 1 Eat: The current in a Sﬂ—mH inductor is given in Fig. P630. Sketch the inductor vullagc. EU} (ma) Figure PIE-3o SOLUTION: VHFO Jon 1mg < t S HMS VCJ) 2' 50m [—50] Wt): ~2-5v’ tgon bums < at \< ‘st Wat) : 50"“[50] \x(:t)= '2’5V Wye) = ENC-50] Chapter 6: Capacitance and Inductance Problem 6.30 2 Irwin, Basic Engineering Circuit Analysis, 9/E \1(1)="2'5V Problem 6.30 . Chapter 6: Capacitance and Inductance ...
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