# boyles-law-lab-answers - unit of time thus the pressure...

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Boyle’s law lab Purpose: to investigate mathematical relationship between pressure and volume Sample calculations: Diameter of piston 2245 2.40 cm (2.30-2.50) Radius 2245 1.20 cm Area 2245 π r 2 2245 4.52 cm 2 (4.15 - 4.91) Book pressure 2245 average book weight area of contact 2245 850 g / 4.52 cm 2 2245 188 g / cm 2 (173 - 205) PV column should be 36,000 all the way down

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Pressure vs. volume 0 500 1000 1500 2000 2500 0 10 20 30 40 volume (cm 3 ) pressure (g/cm 2 ) Pressure vs. 1/Volume 0 500 1000 1500 2000 2500 0.000 0.010 0.020 0.030 0.040 0.050 0.060 0.070 1/volume (cm -3 ) Pressure (g/cm2) y = mx + b P = (constant)(1/V) + 0 PV = constant (answer to both 1 and 2)
Conclusions and Questions 3. If P doubles, V is cut in half. If P is tripled, V becomes 1/3 of its original value. 4. “As the pressure on a gas increases, the volume of the gas decreases proportionally, provided that the temperature and amount of gas remain constant”. I.e. P 1 V 1 = P 2 V 2 . 5. As volume decreases, there are more collisions with the side of the container per

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Unformatted text preview: unit of time, thus the pressure increases. 6. P 1 =103 kPa, V 1 =5.2 L, P 2 =400 kPa, V 2 =? Using Boyle’s law: P 1 V 1 = P 2 V 2 , 103 kPa x 5.2 L = 400 kPa x V 2 V = (103 kPa x 5.2 L) / 400 kPa = 1.34 L 7. P 1 = 700 mm Hg x 1 atm / 760 mm Hg = 0.921 atm , V 1 = 200 ml, P 2 = ?, V 2 = 950 ml Using Boyle’s law: P 1 V 1 = P 2 V 2 0.921 atm x 200 ml = P 2 x 950 ml P 2 = (0.921 atm x 200 ml)/950 ml = 0.194 atm Conclusion • By comparing values in the PV column and via the graph we see that PV = constant • This is called Boyle’s law (after the scientist that first discovered the relationship) • We will be looking more closely at Boyle’s law • For example, using the form P 1 V 1 = P 2 V 2 • Read “Results of Boyle’s Law Experiment” on handout. Do questions 1 – 6. For more lessons, visit www.chalkbored.com...
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boyles-law-lab-answers - unit of time thus the pressure...

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