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# exam-review-answers - 1 19F 9e 9p 10n0 Ar-40 18e 18p 22n0 2...

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1. 19 F: 9e , 9p + , 10n 0 Ar-40: 18e , 18p + , 22n 0 2. a) Al 2 S 3 b) MgO 3. NaF = 4.0 – 0.9 = 3.1: ionic, London. H 2 O = 3.5 – 2.1 = 1.4: dipole-dipole (specifically H-bonding), London. O 2 = 3.5 – 3.5 = 0: London 4. H: 3.03/98 x 100 = 3.1% H P: 30.97/98 x 100 = 31.6% P O: 64/98 x 100 = 65.3% O 5. 4.89 ÷ 6.77 + 1.2782 x 2.78 = 0.722 3 + 3.55 34 = 4.27 57 = 4.28 6. (0.199)(10) + (0.801)(11) = 10.80 1 7. 7.3 mol C 2 H 4 x 6.02x10 23 particles 1 mol C 2 H 4 = 2.64x10 25 atoms x 6 atoms 1 particle C 2 H 4

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4 = 3.8 mol x 159.1 g/mol = 60 6 g 9. 63.2 g C x 1 mol/12.01 g = 5.26 mol (3.01) 8.8 g H x 1 mol/1.01 g = 8.71 mol (4.98) 28.0 g O x 1 mol/16.0 g = 1.75 mol (1) Simplest formula = C 3 H 5 O 10.CH 2 O: 30 g/mol, 180 g/mol ÷ 30 g/mol = 6 Molecular formula: C 6 H 12 O 6 11. 210 83 Bi 4 2 He + 206 81 Tl 75 34 Se 0 –1 e + 75 35 Br 12.# mL O 2 = 1 mL C 4 H 10 x 13 mL O 2 /2 mL C 4 H 10 = 6.5 mL used, 2.5 mL remain 13. # g
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exam-review-answers - 1 19F 9e 9p 10n0 Ar-40 18e 18p 22n0 2...

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