# molar-volume-lab-answers - T 2 = 273 K P 1 V 1 T 1 = P 2 V...

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Molar volume calculations

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Molar volume calculations a) 3.00 cm b) 0.0143 g/cm c) Mass = g/cm x cm = 0.0143 g/cm x 3.00 cm = 0.0429 g d) Moles = g x mol/g= 0.0390 g x 1 mol/24.31 g = 0.00176 5 mol e) Moles H 2 = Moles Mg = 0.00176 5 mol f) should be higher # than g) h) Class average = 44.1 mL i) 101.6 kPa, j) 22 ° C, 295 K k) 2.64 kPa (pg. 464) l) Pgas = Patm - Pvapour = i - k 101.6 kPa - 2.64 kPa = 98.9 6 kPa
V 1 = 44.1 mL, P 1 = 98.9 6 kPa, T 1 = 295 K V 2 = ?, P 2 = 101.325 kPa,
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Unformatted text preview: T 2 = 273 K P 1 V 1 T 1 = P 2 V 2 T 2 (98.9 6 kPa)(44.1 mL) (295 K) = (101.325 kPa)(V 2 ) (273 K) (98.9 6 kPa)(44.1 mL)(273 K) (295 K)(101.325 kPa) = 39.8 6 mL n) 0.00176 5 mol = 39.8 6 mL, 1 mol = 225 87 mL (divide each side by 0.001765 or cross multiply) o) 22.5 9 – 22.4 % error = (22.5 9 - 22.4) / 22.4 x 100% = 0.1 9/22.4 x 100% = 0.8 5 % = V 2 For more lessons, visit www.chalkbored.com...
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## This note was uploaded on 11/09/2011 for the course CHEM 110 taught by Professor Sullivan during the Fall '10 term at BYU.

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molar-volume-lab-answers - T 2 = 273 K P 1 V 1 T 1 = P 2 V...

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