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Unformatted text preview: T 2 = 273 K P 1 V 1 T 1 = P 2 V 2 T 2 (98.9 6 kPa)(44.1 mL) (295 K) = (101.325 kPa)(V 2 ) (273 K) (98.9 6 kPa)(44.1 mL)(273 K) (295 K)(101.325 kPa) = 39.8 6 mL n) 0.00176 5 mol = 39.8 6 mL, 1 mol = 225 87 mL (divide each side by 0.001765 or cross multiply) o) 22.5 9 – 22.4 % error = (22.5 9  22.4) / 22.4 x 100% = 0.1 9/22.4 x 100% = 0.8 5 % = V 2 For more lessons, visit www.chalkbored.com...
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 Fall '10
 Sullivan
 Mole

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