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View Full Document Stoichiometry overview
•
Recall that in stoichiometry the mole ratio
provides a necessary conversion factor:
grams (x)
↔
moles (x)
↔
moles (y)
↔
grams (y)
molar mass of x
molar mass of y
mole ratio from balanced equation
•
We can do something similar with solutions:
volume (x)
↔
moles (x)
↔
moles (y)
↔
volume (y)
mol/L of x
mol/L of y
mole ratio from balanced equation
•
Read pg. 351353.
Try Q 13a.
Ammonium sulfate is manufactured by reacting
sulfuric acid with ammonia. What concentration
of sulfuric acid is needed to react with 24.4 mL
of a 2.20 mol/L ammonia solution if 50.0 mL of
sulfuric acid is used?
Pg. 353, Question 1
1 mol H
2
SO
4
2 mol NH
3
x
# mol H
2
SO
4
=
0.0244 L NH
3
0.0268
4 mol
H
2
SO
4
=
2.20 mol NH
3
L NH
3
x
H
2
SO
4
(aq) + 2NH
3
(aq)
→
(NH
4
)
2
SO
4
(aq)
Calculate mol H
2
SO
4
, then mol/L = mol/0.0500 L
mol/L = 0.0268
4 mol H
2
SO
4
/ 0.0500 L = 0.537 mol/L
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View Full Document Calcium hydroxide is sometimes used in water
treatment plants to clarify water for residential
use. Calculate the volume of 0.0250 mol/L
calcium hydroxide solution that can be
completely reacted with 25.0 mL of 0.125 mol/L
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This note was uploaded on 11/09/2011 for the course CHEM 110 taught by Professor Sullivan during the Fall '10 term at BYU.
 Fall '10
 Sullivan
 Mole, Stoichiometry

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