Exercise6 - 并并并并-并并 并 6 并...

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Unformatted text preview: 并并并并-并并 并 6 并 并并并并并并并并并并并 6.3 ① 并并并并并 6.3 并并并并并 ② 并 A=(0,1,2,7,9,11,16,17,18,19,23,24,25,27,28,30,33,34)并B=(3,4, 5,6,8,10,12,13,14,15,20,21,22,26,29,31)并并并并并 6.3并并并并并并并并并并并并并并并并并并并并 并并 并并 ① 6.3 并并并并并并并并 147 并并并并并并并并并 并并并并并并并并并○(n)并并并并并并并并并并并并并并 并并并(2)并并并 k(m)并并并并并并并并并 k(m)=m/并m,(2.1)并并并并并并并 i*logm 并并并并并并 A 并并并并并并并并并并并并并并并并并并并并并 并并并○(并n)并并并并并并并并(2)并并并 k(m)×并n 并并并并并(3)并并并 k(m)并并并并并并 A并B 并并并并并并并并并并并并并并并并 k(m)×(并n+1)并 并 k(m)=m/并m 并并并并并 m×(并n+1)/ 并n并并并并 m 并 n 并并并并并并并 6.3 并并并并并并并○(n)并 A并B ② 并并并并并并并并并并 n=18并m=16并k(16)=16/并16=4并并并并并 6.3 并并并并并并并并并并并并并并并并并并并 n=18并m=16并k(16)=16/并16=4并并并并并 6....
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This note was uploaded on 11/08/2011 for the course CS 11004 taught by Professor Zhiyifang during the Winter '11 term at Tianjin University.

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Exercise6 - 并并并并-并并 并 6 并...

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