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Fall 2011 Exam II Practice Worked Examples 1-11

# Fall 2011 Exam II Practice Worked Examples 1-11 - Exam II...

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1 Calculators of this type are not allowed for quizzes and the exams. This type is OK. Exam II Tuesday November 8, 2011 in class (lecture). 7:15 PM – 8:35 PM Copyright G Hall November 2011

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Exam II Tuesday November 8, 2011 In Lecture Chapters 13, 14, 15 13.1 up to 15.11 See pages 527-664 Study the concepts and work some problems. Don’t try to guess what material will be on the exam based on this practice exam. There is no relationship between the practice exam and the exam on Tuesday. Copyright G Hall November 2011 2
P1 What is the K w of pure water at 50.0°C, if the pH is 6.630? A. There is not enough information to calculate the K w . B. 2.13 × 10 -14 C. 1.00 × 10 -14 D. 5.50 × 10 -14 E. 2.34 × 10 -7 [H 3 O + ] = 10 -6.63 = 2.34 x 10 -7 = [OH - ] K w = [H 3 O + ] [OH - ] = 5.5 x 10 -14 Copyright G Hall November 2011 3

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P2 The unit of the rate constant for the following rate law equation is: Rate = k[A] 2 [B] 2 A. M -3 s -1 B. M -4 s -1 C. M -2 s -1 D. s -1 E. Ms -1 Rate = k[M A ] 2 [M B ] 2 M 4 for the rate to be in M/s, k = M -3 s -1 Copyright G Hall November 2011 4
P3 The t 1/2 of a second-order decomposition (A ------> Products), is 26 hours when the initial concentration of A is 0.256 M. How long would it take for the concentration of A to drop from 0.256 M to 0.064 M? C. 78 hours First solve for k from t 1/2 = (1/k[A] o ) 26 hrs = (1/k[0.256] o ); k = 0.15 Plug into (1/[A] - 1/[A] o ) = kt (1/[0.064] - 1/[0.256] o ) = 0.15 t And solve for t.

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Fall 2011 Exam II Practice Worked Examples 1-11 - Exam II...

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