Fall 2011 Exam II Practice Worked Examples 12-21

Fall 2011 Exam II Practice Worked Examples 12-21 - Exam II...

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1 Calculators of this type are not allowed for quizzes and the exams. This type is OK. Exam II Tuesday November 8, 2011 in class (lecture). 7:15 PM – 8:35 PM Copyright G Hall November 2011
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Exam II Tuesday November 8, 2011 In Lecture Chapters 13, 14, 15 13.1 up to 15.11 See pages 527-664 Study the concepts and work some problems. Don’t try to guess what material will be on the exam based on this practice exam. There is no relationship between the practice exam and the exam on Tuesday. Copyright G Hall November 2011 2
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P12 Copyright G Hall November 2011 3 The molarity of a reactant in a second-order reaction falls from 0.150 M to 0.130 M in 30.0 s. What is the instantaneous rate of disappearance of the reactant at 30.0 s? (1/[A] - 1/[A]o) = kt 1/0.130 – 1/0.150 = k(30 s) Solving for k gives k = 0.0342 Rate =k[A] 2 Rate = 0.0342[0.130] 2 = 5.78E-4 M/s
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P13 Copyright G Hall November 2011 4 Write the expressions for the rate for each step and substitute into the rate law. This will give E. For I., k 1 [A][B]/k -1 =k -1 [E]/k -1 Substitution into the slow step gives rate = k[E][B] = k 1 /k -1 K[A][B] 2 which is not the rate law rate =k[A] 2 [B] Do the same for the other two mechanisms which will give the rate law.
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This note was uploaded on 11/09/2011 for the course GEN CHEM 162 taught by Professor Tavss during the Spring '11 term at Rutgers.

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Fall 2011 Exam II Practice Worked Examples 12-21 - Exam II...

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