Unformatted text preview: b = 5, then both equations are made true. [3(– 6) + 4(5) = 2 AND 6(– 6) + 8(5) = 4] What we have here is really only one equation written in two different ways. In this case, the second equation is actually the first equation multiplied by 2. The solution for this situation is either of the original equations or a simplified form of either equation....
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This note was uploaded on 11/09/2011 for the course MATH 1310 taught by Professor Staff during the Fall '07 term at Texas State.
- Fall '07