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Example15 - following chart can be helpful number value...

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Example 2 Sid has $4.85 in coins. If he has six more nickels than dimes and twice as many quarters as dimes,  how many coins of each type does he have? First, circle what you must find—  the number of coins of each type.  Let  x  stand for the number of  dimes. Then  x  + 6 is the number of nickels, and 2  x  is the number of quarters. Setting up the 
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Unformatted text preview: following chart can be helpful. number value amount of money dimes x .10 .10 x nickels x + 6 .05 .05( x + 6) quarters 2 x .25 .25(2 x ) Now, use the table and problem to set up an equation. So, there are seven dimes. Therefore, there are thirteen nickels and fourteen quarters....
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