Mixture Problems

Mixture Problems - x Now make a chart for the cost of each...

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Mixture Problems Here are some examples for solving mixture problems.   Example 1 Coffee worth \$1.05 per pound is mixed with coffee worth 85¢ per pound to obtain 20 pounds of a  mixture worth 90¢ per pound. How many pounds of each type are used? First, circle what you are trying to find—  how many pounds of each type.  Now, let the number of  pounds of \$1.05 coffee be denoted as  x . Therefore, the number of pounds of 85¢-per-pound coffee  must be the remainder of the twenty pounds, or 20 –

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Unformatted text preview: x . Now, make a chart for the cost of each type and the total cost. cost per lb. × amount in Ibs. = total cost of each \$1.05 coffee \$1.05 x \$1.05 x \$ .85 coffee \$ .85 20 – x \$ .85(20 – x ) mixture \$ .90 20 \$ .90(20) Now, set up the equation. Therefore, five pounds of coffee worth \$1.05 per pound are used. And 20 – x , or 20 – 5, or fifteen pounds of 85¢-per-pound coffee are used....
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This note was uploaded on 11/10/2011 for the course MATH 1310 taught by Professor Staff during the Fall '07 term at Texas State.

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Mixture Problems - x Now make a chart for the cost of each...

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