ch6+1410+FA11

ch6+1410+FA11 - Chapter 6 Momentum and Collisions Practice...

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Momentum and Collisions Chapter 6
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Practice Questions from SV-Ch06 Impulse and Momentum Questions Problems: 1, 4, 5, 7, 9, 13, 15 Conservation of Momentum Questions Problems: 19, 20, 22
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The linear momentum of an object of mass m moving with a velocity is deFned as the product of the mass and the velocity SI Units are kg m / s Vector quantity, the direction of the momentum is the same as the velocity’s Momentum
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Applies to two-dimensional motion Momentum components
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SV-Ch06-P05 A pitcher claims he can throw a 0.145Fkg baseball with as much momentum as a 3.00Fg bullet moving with a speed of 1.50 × 10 3 m/s. (a) What must the baseball’s speed be if the pitcher’s claim is valid? (b) Which has greater kinetic energy, the ball or the bullet?
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SV-Ch06-P05 - Solution ( a ) If , then ball bullet p p ± ² ± ² 33 3.00 10 kg 1.50 10 m s 31.0 m s 0.145 kg bullet bullet ball ball mv v m ´ uu (b) The kinetic energy of the bullet is ± ² ± ² 2 -3 3 2 3 3.00 10 kg 1.50 1 3.38 10 J 22 bullet bullet bullet KE m v u while that of the baseball is ±² 2 2 0.145 kg 31.0 m s 1 69.7 J ball ball ball KE m v The bullet has the larger kinetic energy by a factor of 48.4.
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In order to change the momentum of an object, a net force must be applied Why? Newton’s 2nd and Momentum ~ F net = m ~ a ~ F net = m Δ ~ v Δ t ~ F net = m ( ~ v f - ~ v i ) Δ t ~ F net = ( m ~ v f - m ~ v i ) Δ t ~ F net = ( ~ p f - ~ p i ) Δ t
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in more compact form: Or in other words, momentum changes when a force acts during a time interval This particular equation applies to constant or average forces.
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This note was uploaded on 11/09/2011 for the course PHYS 1410 taught by Professor Staff during the Fall '08 term at Texas State.

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ch6+1410+FA11 - Chapter 6 Momentum and Collisions Practice...

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