SCM_HW_2(1)

SCM_HW_2(1) - Name Email ID Homework 2 Spring 2011 Section...

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5) b) 25th percentile = 8,400,000 75th percentile = 22,650,000 11) Sample variance = =(4+1+9)/2 7 The 25th percentile means that 25% of the companies have sales less than \$ 8.4 mil ion. The 75th percentile means that 75% of the companies have sales less than \$ 22.65 mil ion. Sample Standard Deviation = =√7 2.65 12) c) Minimum \$6,600,000.00 6) CV = =((2.65)/7)*100 maximum \$450,000,000.00 37.85714 Average \$33,536,000.00 7) I would prefer a the test score of 75 cause I would be in the third deviation from the mean which Median \$13,000,000.00 means that I would have done bet er than the rest compared to what I would do with a score of 80 when the average is 68, when the scores are standardised. Thus I would least prefer to have the Standard Deviation \$84,397,748.20 score of test 2. The Mean is larger than the median as the data is skewed positive. 1) Average = (40+40+40+80)/ 4 = 50 8) d) Weighted Average = (40*40) + (40*40)+ (40*40)+(80*80) / (40+40+40+80) = 56 2) False. The Range can be same but the variability may not be same as the data may be
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This note was uploaded on 11/08/2011 for the course SCM 200 taught by Professor Kumarsanjay during the Spring '08 term at Penn State.

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