lab 3 quiz key - If a 3 kg ball is dropped from a height of...

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If a 3 kg ball is dropped from a height of 33 meters, what will its kinetic energy be just before landing? (show calculations using work/energy equations.) (2 pts) For this question, we know that there is no potential energy right before the ball lands, because all of the energy is kinetic energy. But, the conservation of momentum law states that energy is always conserved, so in this case, the change in Potential Energy from the peak to the bottom will be equal to the change in Kinetic Energy, PE (initial)= KE (final), giving us the kinetic energy of the ball before landing. So we have PE = mgh PE = 9.81(33)(3kg) = 971.2 J So the ball has a Kinetic Energy of 971.2 J just before landing. Or you could use projectile equations to calculate the velocity of landing and calculate the energy that we. v f 2 = v i 2 + 2g Dy vf=25.45 m/s K=1/2mv 2 K=971 J If a 3 kg ball is dropped from a height of 33 meters, how fast will it be traveling just before landing? (2 pts) To find the velocity of the ball, need to use the Kinetic Energy value for this problem, given
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This note was uploaded on 11/10/2011 for the course KNH 381LAB taught by Professor Staff during the Summer '11 term at Miami University.

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lab 3 quiz key - If a 3 kg ball is dropped from a height of...

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