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Unformatted text preview: following set of parametric equations (with θ as the parameter) for the curve. Now, we will need the following derivatives. The derivative is then, Derivative with Polar Coordinates Note that rather than trying to remember this formula it would probably be easier to remember how we derived it and just remember the formula for parametric equations. Let’s work a quick example with this. Example 1 Determine the equation of the tangent line to at . Solution We’ll first need the following derivative. The formula for the derivative becomes, The slope of the tangent line is, Now, at we have . We’ll need to get the corresponding xy coordinates so we can get the tangent line. The tangent line is then, For the sake of completeness here is a graph of the curve and the tangent line....
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This note was uploaded on 11/10/2011 for the course MATH 136 taught by Professor Prellis during the Fall '08 term at Rutgers.
 Fall '08
 prellis
 Calculus, Polar Coordinates

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