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EAS207-Lec-11 - Chg f 9km —— 3 Eli ~ ‘ EQURTsONS ox...

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Unformatted text preview: Chg f 9km —— 3% Eli. ' ~» ‘ EQURTsONS ox: EQUIUBRIUM né. . ”'- W Ncessmg COMUCYMD ffowr a chyfoq bo<§lxé {o be M EWQibflum one: 52 2. o m} 311% r: O {D W above QomoQ'me'm ox? suffi‘dede "Q0 ‘QO’wix/s om \mtiqfla Sjtoix‘mQYa booig M a 31(qu afi'eq/umbn‘mm- ——~ m fiuwd‘omax QWUOJUW 0/; S’todcfw Cow 0X30 be mfi’t‘cm CM p...” E1 F4720 ifixfi +€CT-O ’1 Cox/kw» abovx’k OW? Pomk M @6108 MMS’C be ZQYO‘ 2’sz 1MP, + '3sz +75 XE“: o 3 2m: (JJEWE +Q+EWE+C0H§V§ = ‘ZMQ‘V‘ +0\X (5+E553) HZMG +o\ x FI2 --' MYQ 0W6 WMQ 2 ‘V‘EQPQWW Wi\b¥\\fiw {0" 0M» Simaw ghee-bowl) 51AAQ V Y\ be L (Q “k‘k\'@ \V\ %QV\9_ QX \' Ar, \ACK‘A 68 S‘kax (A {01 126 My - OR SSW ff {Es <3va 629.0%"de Reactions One Collinear Force One Force Normal to the Supporting Surface Contact with a Smooth Surface Roller Support ‘ One Force Normal to the Supporting Surface Lll :»\\ Eight, E . ‘Mbfimm @ / Application to Engineering Design for Human Factors shows an airport luggage carrier and its free—body diagrz the tilted position. If the luggage carrier supp 8 in. b = 16 in., and d = 48 in., E Figure held in equilibrium in W .. 50 lb the angle a — —,300 a: must the user exert? STRATEGY The unknown reactions on the free— body diagram are the force F an force N exerted by the floor. If we sum moments about the center of we obtain an equation in which F 18 the only unknown reaction SOLUTlON Summing moments about C , ‘2 M(p0intC) = d”: COS a) + GOV Sin a) —— [)(W COS (I) : O and solving for F , we obtain ’(b-atana)W F— d . Substituting the values of W, a, a, b, and d, the solution is F = ll.9 lbr l l i 12 l l l Figure a. ~ ; (a) If both people sit at the ends of the seesaw, the heavier one sinks. (b) The seesaw and people in equilibrium. (c)/The free-body diagram of the seesaw, showing the ights of the people and the reactions at the pin i, Sapport. W The mobile is in equilibrium. The fish 8 weighs 27 oz Determine the weights of the fish A C . k . , and D. Tl -- crossbars are Negligible.) ( 10 weights of the 23‘“ ma“ 4 ' ’Bu. bows. Fx‘von M44.“ ng==0 :3 KT3C0'6>*5000(0*6):0 ©E§Efl ipx :20 :3 ~T+szo 2% :0 => Dd ~S‘oo<)~\%2_:o @ D ='— 69'62N 2MB: =5 (C3) (4)“GDJ) (figzo :DKCB—zusrs N] ngiO .3 #04003) +CC>O (2'9) 4635(4) 'CFMz-D =0 ~ I ._..~. C 1243007+M3333 . z) ’ ’1 EXCAVAMQ? , 4 ' flax-«3U “nu-“mi...“ , Shppofix‘ V {07020 0W Pr GM 8 ? EMF: 2? ~(BOOJC3'7COSZOU) HQMZSM 30°) '7‘“ CC3)CZCOSZOO) :0 W ”"961” + Cx +1.73% :0 M (ix : {Maya—r7325? HQ) 27310 :9 flx#c><:0 :9' HXZCX Q 557:0 T9 Aficafioom :{W‘r ‘i \ ...
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