s1111 - Solution for assignment 11a: For a bilinear kinetic...

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Unformatted text preview: Solution for assignment 11a: For a bilinear kinetic Energy we find by differentiation and carrying the sum over i out qi ˙ i ∂T = ∂ qi ˙ qi ˙ i ∂ ∂ qi ˙ qi ˙ ajk qj qk = ˙˙ j,k i ajk (δij qk + qj δik ) ˙ ˙ j,k ajk (qj qk + qj qk ) = 2 T . ˙˙ ˙˙ = j,k Solution for assignment 11b: Motivation of generalized momentum definition. ∂ ∂ xi ˙ 1 m v 2 − V (x) 2 = m xi = p i . ˙ ...
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