s1111 - Solution for assignment 11a For a bilinear kinetic...

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Solution for assignment 11a: For a bilinear kinetic Energy we find by differentiation and carrying the sum over i out X i ˙ q i ∂T ˙ q i = X i ˙ q i ˙ q i X j,k a jk ˙ q j ˙ q k = X i ˙ q i X j,k a jk ( δ ij ˙ q k + ˙ q j δ ik ) = X j,k a jk ( ˙ q j ˙ q k + ˙
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