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problem29_38

problem29_38 - 29.38 a)  E = ρJ = b)  ρI(2.0 × 10...

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Unformatted text preview: 29.38: a)  E = ρJ = b)  ρI (2.0 × 10 −8 Ωm)(16 A) = = 0.15 V / m. A 2.1 × 10 -6 m 2 dE d ρI ρ dI 2.0 × 10 −8 Ωm = = = (4000 A s ) = 38 V m ⋅ s. dt dt A A dt 2.1 × 10− 6 m 2 dE 2 = ε 0 (38 V s ⋅ s) = 3.4 × 10 −10 A m . c)  j D = ε 0 dt d) i D = j D A = (3.4 × 10 −10 A/m 2 ) (2.1 × 10 −6 m 2 ) = 7.14 × 10 −16 A µ 0 I D µ 0 (7.14 × 10 −16 A) ⇒ BD = = = 2.38 × 10 − 21 T, and this is a   2πr 2π (0.060 m) µ 0 I c µ 0 (16 A) = = 5.33 × 10 −5 T. negligible contribution. Bc = 2πr 2π (0.060 m) ...
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