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# Test%202%20Practice%20Test%20Answers0 - CHEM 1212 Practice...

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CHEM 1212 Practice This is only to help you prepare for the upcoming test. Of course you should be reviewing and using all available resources for your preparation. 1. Determine the rate law when given the following data (at 25 Celsius): 3 A( aq ) + 2 B( aq ) 4 C( aq ) Rate mol/L-s A mol/L B mol/L 0.00021 0.150 0.120 0.00336 0.150 0.480 0.00021 0.450 0.120 0.00336 0.450 0.480 The rate of the reaction does not change when [A] is increased, so the reaction order for [A] is zero. The reaction rate is multiplied by 16 when the [B] is quadrupled, so the reaction order of [B] is second. Rate = k[B] 2 2. Solve for the rate constant k for the above rate law, including units for k. 0.00336 = k (0.480) 2 k = 0.0146 M -1 s -1 Rate = 0.0146[B] 2 3. What is the rate of the reaction if [B] is 0.35M? [include units in your answer] Rate = 0.0146(0.35) 2 Rate = 0.00179 Ms -1 4. Write an equation that relates [B] t to k, t and [B] 0 (1/[B] t ) = kt + (1/[B] 0 ) 5. If the initial concentration of [B] is 0.35 M, what is the concentration of [B] 18 ? (1/[B]

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Test%202%20Practice%20Test%20Answers0 - CHEM 1212 Practice...

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