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Experiment 1 and 2 Solution SUMMARY SHEET

# Experiment 1 and 2 Solution SUMMARY SHEET - 1 SUMMARY SHEET...

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SUMMARY SHEET EXPERIMENT 1 1. FOR WATER AND RED LIGHT AT EXTREME END OF SPECTRUM k = 1 First Order Rainbow θ 1 =129.0° 137.0° φ 1 = 137.0 ±5.0° k = 2 Second Order Rainbow θ 2 = 129.0° φ 2 = 231.0 ±3.0° k = 5 Fifth Order Rainbow θ 5 = 126.0° φ 5 = 486.0 ±4.0° 2. LIQUIDS A AND B USING SECOND ORDER RAINBOWS For Liquid A θ 2 = 105.0° φ 2 = 255.0 ±3.0° For Liquid B θ 2 = 89.5° φ 2 = 270.5 ±3.0° Gradient of graph = 0.84 ±0.07 Extrapolated, n =2, θ 2 , value of φ = 304 ±25 o 1 θ 2 = 0.0.. o 0 1 2 3 4 5 500 400 300 200 100 o k φ k Figure E 1.1. φ 2 = 0.0.. o For n = 1

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2 0.6 0.7 0.8 0.9 1.0 Exact theory value 1.0 0.9 0.8 0.7 1/ n Figure E 1.2
SUMMARY SHEET EXPERIMENT 2 Is the total momentum conserved? YES /NO Accuracy of computer calculation 1 . 0 0000018 . 0 100 0.002% 0:1 (RMS velocity = 0.1) Time Total Energy 0 -1.61499 2 -1.62886 4 -1.62878 6 -1.62301 12 -1.62882 18 -1.62599 24 -1.62796 30 -1.62703 50 -1.62753 70 -1.62676 90 -1.62580 130 -1.62713 180 -1.62409 Does the system conserve energy? YES/NO (~ ±1%) Equilibrium value of E k * Equilibrium time SD (Average 24 to 180) (see Fig. E 2.1 ) = 0.534 ±0.05 2245 (10 to 20 ) 1 . 0 × Value of S recorded > 20, e.g. 60 Value of α (for SD =60) (see Fig. E2.2 ) = 0.503 Accuracy of α = ±0.02 For what time number range is graph, obtained using first value of SR , linear? SZ = 18 to 24 3

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