Experimental Exam_A - 1 39 1986 INTERNATIONAL PHYSICS O...

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39 1986 INTERNATIONAL PHYSICS OLYMPIAD EXPERIMENT 1. 2½ hrs APPARATUS 1. Spectrometer with collimator and telescope. 2. 3 syringes; one for water, one for liquid A and one for liquid B. 3. A beaker of water plus two sample tubes containing liquids A and B. 4 3 retort stands with clamps. 5. 12V shielded source of white light. 6. Black card, plasticine, and black tape. 7. 2 plastic squares with holes to act as stops to be placed over the ends of the telescope, with the use of 2 elastic bands. 8. Sheets of graph paper. 9. Three dishes to collect water plus liquids A and B lost from syringes. Please complete synopsis sheet in addition to answering this experimental problem. 1 Pendant drop Collimator Telescope Light Drop θ Plan of Apparatus
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INSTRUCTIONS AND INFORMATION 1. Adjust collimator to produce parallel light. This may be performed by the following sequence of operations: (a) Focus the telescope on a distant object, using adjusting knob on telescope, so that the cross hairs and object are both in focus. (b) Position the telescope so that it is opposite the collimator with slit illuminated so that the slit can be viewed through the telescope. (c) Adjust the position of the collimator lens, using the adjusting knob on the collimator, so that the image of the slit is in focus on the cross hairs of the telescope's eyepiece. (d) Lock the spectrometer table, choosing an appropriate 'zero' on the vernier scale, so that subsequent angular measurements of the telescope's position can conveniently be made. 2. Remove the eyepiece from telescope and place black plastic stops symmetrically over both ends of the telescope, using the elastic bands, so that the angle of view is reduced. 3. Open up collimator slit. 4. Use the syringes to suspend, vertically, a pendant drop symmetrically above the centre of the spectrometer table so that it is fully illuminated by the light from the collimator and can be viewed by telescope. 5. The central horizontal region of the suspended drop will produce rainbows as a result of two reflections and k (k = 1,2,. ..) internal reflections of the light. The first order rainbow corresponds to one internal reflection. The second order rainbow corresponds to two Internal reflections. The k'th order rainbow corresponds to k internal reflections. Each rainbow contains all the colours of the spectrum. These can be observed directly by eye and their angular positions can bed accurately measured using the telescope. Each rainbow is due to white light rays incident on the drop at a well determined angle of incidence, that is different for each rainbow. 6. The first order rainbow can be recognized as it has the greatest intensity and appears on the right hand* side of the drop. The second order rainbow appears with the greatest intensity on the left hand * side of the drop. These two rainbows are within an angular separation of 20° of each other for water droplets. The weak intensity fifth order rainbow can be observed on the right hand side of
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This note was uploaded on 11/08/2011 for the course PHYS 0000 taught by Professor Na during the Spring '11 term at Rensselaer Polytechnic Institute.

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Experimental Exam_A - 1 39 1986 INTERNATIONAL PHYSICS O...

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