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# p_a - Question Pink 1.1 Period = 3.0 days = 2.6 105 s(0.4 2...

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Question “Pink” 1.1 Period = 3.0 days = s 10 6 . 2 5 × . (0.4) Period = ω π 2 (0.2) 1 5 s rad 10 4 . 2 - - × = ω . (0.2) 1.2 Calling the minima in the diagram 1, 90 . 0 0 1 = = α I I and 63 . 0 0 2 = = β I I , we have: α 1 1 4 1 2 2 1 2 1 0 = + = T T R R I I (0.4) α β = - - = 4 1 2 2 1 2 1 2 1 1 T T R R I I (0.4) (or equivalent relations) From above, one finds: 6 . 1 1 2 1 2 1 = - = R R R R β α (0.2+0.2) and 4 . 1 1 1 2 1 4 2 1 = - - = T T T T α β (0.2+0.2) 2.1) Doppler-Shift formula: c v Δ 0 λ λ (or equivalent relation) (0.4) Maximum and minimum wavelengths: 7 . 5897 max , 1 = λ Å , 1 . 5894 min , 1 = λ Å 0 . 5899 max , 2 = λ Å , 8 . 5892 min , 2 = λ Å Difference between maximum and minimum wavelengths: 6 . 3 1 = Δ λ Å , 2 . 6 2 = Δ λ Å (All 0.6) Using the Doppler relation and noting that the shift is due to twice the orbital speed: (Factor of two 0.4) 0 1 1 2 λ λ Δ = c v 4 10 2 . 9 × = m/s (0.2) 0 2 2 2 λ λ Δ = c v 5 10 6 . 1 × = m/s (0.2)

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p_a - Question Pink 1.1 Period = 3.0 days = 2.6 105 s(0.4 2...

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