# Sol-Ch33 - Exercises 1(a i o = v o ω L = 7.96A(b f 2 = F...

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Unformatted text preview: Exercises 1. (a) i o = v o / ω L = 7.96A; (b) f 2 = F 1 /0.3 = 200 Hz 2. (a) i o = v o ω C = 1.10 A; (b) f 2 = 1.3 × 50 = 65Hz 3. (a) ω L = 1/ ω C, thus f o = 1/2π (LC) – 1/2 = 5.03 kHz; (b) f = (5) 1/2 f o = 11.25 kHz; (c) f = f o /(5) 1/2 = 2.25 kHz 4. L = X L / ω = 0.1 H; then i o = v o / ω L = 5.40 A 5. (a) Q o = i o / ω = v o C = 1.7 mC; (b) i o = ω Q o = 0.64ª 6. (a) i o = v o / ω L = 0.921 A; (b) 0 (c) 0.5 = cos( ω t), thus ω t = π/3; 5π/3 i = i o sin( ω t) = ±i o (0.866) = ±0.798 A (d) p = i o v o L sin(2 ω t)/2 = 23.0 W 7. (a) i o = v o ω C = 1.3 A; (b) zero; (c) –0.5 = cos( ω t), ω t = 2π/3, 4π/3 i = i o sin( ω t) = ±1.13 A; (d) p = –i o v o C sin(2 ω t)/2 = –13.2 W 8. (a) ω = 1/CX C = 1/11C, thus ω L = L/11C = 3.03 Ω (b) f o = 1/2π(LC) 1/2 = 4590 Hz 9. (a) i = i o sin( ω t) = 2.39sin(0.2π) = 1.40 A, p = i o v o L sin(2 ω t)/2 = 68.2 W; (b) i o = v o / ω t, so f = v o /2πi o L = 66.3 Hz 10. (a) i = i o sin( ω t) = 1.06 A; p = –i o v o C sin(2 ω t)/2 = –62 W (b) f o = i o /2πv o C = 111 Hz 11. Z 2 = R 2 + 1/( ω C) 2 ; (10.8) 2 = R 2 + 1.665 × 10 –7 /C 2 ; (18.8) 2 = R 2 + 6.333 × 10 –7 /C 2 CHAPTER 33 Solve to find C = 44.4 µF, R = 5.67 Ω 12. Apply Z 2 = R 2 + ω 2 L 2 and solve: R = 13 Ω, L = 40 mH 13. i o = 0.5 A = v o /Z, Z 2 = R 2 + 10 4 (5L – 2) 2 Find L = 75.6 mH, 724 mHFind L = 75....
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## This note was uploaded on 11/09/2011 for the course EE EE taught by Professor Ee during the Spring '11 term at National Chiao Tung University.

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Sol-Ch33 - Exercises 1(a i o = v o ω L = 7.96A(b f 2 = F...

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