# Sol-Ch32 - CHAPTER 32 E xercises 1(a L = o n 2 Al = 152...

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Exercises 1. (a) L = µ o n 2 Al = 152 µHi; (b) d I /dt = ξ /L = 26.3 A/s 2. (a) L = ξ /(d I /dt) = µ o N 2 A/ l , thus N = 47.5 (b) B = µ o n I = 7.16 ×  10 –4 T 3. (a) Ф = L I /N = 4.8 Wb; (b) ¦ ξ ¦ = L d I /dt = 42.5 4. (a) (L I 0 /τ)e –t/ Ƭ ; (b) L(2bt – a); (c) – ω L I 0 cos( ω t) 5. L = N Ф / I = 375µH; then ¦ ξ ¦ = L d I /dt = 9.38 mV 6. L = ξ /(d I /dt) = 4.5 ×  10 –4 H; then Ф = L I /N = 33.8 µWb 7. L = ξ /(d I /dt) = 93.8mH 8. L = (µ o 1/2π) ln(b/a) = 9.32 µH 9. M = µ o N 1 n 2 A 2 = µ o (5)(360/0.2)(π)(1.7 ×  10 –2 ) 2 = 8.56mH 10. ξ = M d I /dt = 1 V 11. (a) M = µ o N 1 n 2 A 2 = 80.4 µH; (b) ξ   = M d I /dt = 402 µV 12. (a) M = N 2 Ф 21 / I 1 = 1.5 ×  10 –9 H; (b) ξ   = M d I 2 /dt = 6 ×  10 –8 V 13. (a) d Ф = B dA = (µ o N I /2πr)(h dr), thus Ф = µ o hN 1 I 1 /2π ln(b/a); (b) M = N 2 Ф 21 / I 1 = (µ o hN 1 N 2 /2π) ln(b/a) 14. M = N 1 Ф 12 / I 2 , and Ф 1 2 = B 2 A 1 cos60 ° = (µ o n 2 I 2 )A 1 cos60 ° Thus M = 0.5µ o n 2 N 1 A 1 = 19 µH 15. (a) Ф 11 = L 1 I 1 /N 1 = 0.60 mWb; (b) Ф 12 = M I 2 /N 1 = 0.39 mWb; CHAPTER 32

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(c) Ф 21 = M I 1 /N 2 = 0.14mWb; (d) ξ 11 = L 1 d I 1 /dt = 80mV; (e) ¦ ξ 1 2 ¦ = M d I 2 /dt = 12.6 mV; (f) ξ 21 = M d I 1 /dt = 28 mV 16. (a) d I /dt = ( ξ /L), so I = ξ t/L (b) I = ( ξ /R)[1 – (1 – Rt/L)] = ξ t/L 17. (a) I = ( ξ /R)(1 – e –t/ Ƭ ) = 0.279 A; (b) ξ L = L d I /dT = ξ exp( –t/ Ƭ   ) = 10.3 V; (c) From 0.8 = (1 – e –t/ Ƭ ), t = – Ƭ ln(0.2) = 536 ms 18. (a) 3T 1 /2 = 3(0.693L/R) = 0.693 s (b) ξ L
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Sol-Ch32 - CHAPTER 32 E xercises 1(a L = o n 2 Al = 152...

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