# Sol-Ch27 - Exercises 1(a In 1 s N = ΔQ/e = 1.19 × 10 16(b...

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Unformatted text preview: Exercises 1. (a) In 1 s, N = ΔQ/e = 1.19 × 10 16 . (b) J = I/A = 2.42 × 10 3 A/m 2 2. (a) J = I/A = 0.318 A/m 2 ; (b) J = nev, so n = J/ev = 3.97 × 10 11 m –3 3. (a) J = I/A = nev, so v = I/Aev = 1.07 × 10 –5 m/s; 4. (a) J = I/A = 6.37 x 10 6 A/m 2 (b) E = ρ J = 0.108 V/m (c) J = nev, so v = J/ne = 4.68 × 10 –4 m/s (d) Δt = d/v = 6.41 x 10 7 s = 2.03 y. 5. (a) J = I/A = 2.83 × 10 6 A/m 2 ; (b) E = ρ J = 4.81 × 10 –2 V/m 6. (a) J = I/A = 7.21 × 10 6 A/m 2 (b) v = J/ne = 5.30 × 10 –4 m/s 7. I = Q/T = ev/2πr = 1.06 mA 8. Q = ∫ I dt = [2t3/3 – 3t 2 /2 +5t] =61.5 C 9. (a) J= I/A = 6.79 × 10 6 A/m 2 ; (b) v = J/ne = 4.24 × 10 –4 m/s; (c) E = ρ J =0.19 V/m 10. ρ = VA/Il = 1.14 × 10 –6 Ω ‧ m 11. I = VA/ ρ L = 6.85 × 10 –5 A 12. L 1 A 1 = L 2 A 2 , but given A 2 = A 1 /2, and L 2 = 2L 1 R 2 = ρ L 2 /A 2 = 4R 1 CHAPTER 27 13. R = ρ L/A = ρ l /π(b 2 – a 2 ) 14. R = Ro [1 + α Δt] = 1.27 Ω 15. ΔT= (R/R o – 1)/ α = 128 ° C, so T = 148 ° C 16. α = (R/R o – 1)/ ΔT = 2.08 × 10 –3 ° C –1 17. L α 1/ ρ , so L C u /L A l = 2.8/1.7 = 1.65 18. ΔR = R o 1 α 1 ΔT + R o 2 α 2 ΔT = 0, so R 0 1 /R 0 2 = – α 2 / α 1 = 5.4 R 0 1 /(R o 1 /R o 2 ) = 5.9 = 55.5%....
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## This note was uploaded on 11/09/2011 for the course EE EE taught by Professor Ee during the Spring '11 term at National Chiao Tung University.

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Sol-Ch27 - Exercises 1(a In 1 s N = ΔQ/e = 1.19 × 10 16(b...

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