Assignment 2

# Assignment 2 - Assignment 2 Question 1 (A): Compute the...

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Assignment 2 Question 1 (A): Compute the sample means and the sample standard deviations of each population. On excel: data/ data analysis/Descriptive statistics and then select population with label . Population 1 Population 2 Mean 19946.45017 Mean 14898.13138 Standard Error 323.3333093 Standard Error 206.3901562 Median 20195.4669 Median 15079.35228 Mode #N/A Mode #N/A Standard Deviation 2891.98103 6 Standard Deviation 1913.983569 Sample Variance 8363554.31 2 Sample Variance 3663333.104 Kurtosis 0.132282807 Kurtosis 0.170215451 Skewness 0.17804706 3 Skewness 0.181859584 Range 15036.4576 3 Range 10024.30508 Minimum 12768.5348 7 Minimum 10179.02324 Maximum 27804.9924 9 Maximum 20203.32833 Sum 1595716.01 4 Sum 1281239.299 Count 80 Count 86 Confidence Level(95.0%) 643.578842 5 Confidence Level(95.0%) 410.3589159 Population 3 Population 4 Mean 24871.06132 Mean 20092.90351 Standard Error 319.715166 7 Standard Error 222.6624488 Median 24994.9641 3 Median 20148.74599 Mode #N/A Mode #N/A Standard Deviation 2750.29385 7 Standard Deviation 2135.703182 Sample Variance 7564116.297 Sample Variance 4561228.08 Kurtosis 0.145611093 Kurtosis 0.273547622 Skewness 0.25147743 1 Skewness 0.304968253 Range 14034.0271 2 Range 11026.73559 Minimum 18250.6325 4 Minimum 14896.92557 Maximum 32284.6596 6 Maximum 25923.66116 Sum 1840458.53 7 Sum 1848547.123 Count 74 Count 92 Confidence Level(95.0%) 637.1913992 Confidence Level(95.0%) 442.2915915

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Question 1 (B): Compute a 95% confidence interval estimate for the mean salary of each population. Upper interval = mean + confidence level Lower interval = mean – confidence level Population 1: Confidence interval estimate Upper Interval 20590.03 Lower interval 19302.87 Population 2: Confidence interval estimate Upper Interval 15308.49 Lower interval 14487.77 Population 3: Confidence interval estimate Upper Interval 25508.25 Lower interval 24233.87 Population 4: Confidence interval estimate Upper Interval 20535.2 Lower interval 19650.61 Question1 (c): Compute a 95% confidence interval estimate for the standard deviation of each population’s salary . Population 1: n= 80, s= 2891.98 With excel: =CHIINV(0.025,79) With excel: =CHIINV(0.975,79) 95% confidence interval estimate for standard deviation= = [2502.8732, 3425.4722] Population 2: n=86, s= 1913.98 With excel: =CHIINV(0.025,85) With excel: =CHIINV(0.975,85) 95% confidence interval estimate for standard deviation= = [1664.4751, 2252.1804] Population 3: n= 74, s= 2750.29 With excel: =CHIINV(0.025,73)
With excel: =CHIINV(0.975,73) 95% confidence interval estimate for standard deviation= = [2367.4813, 3281.9415] Population 4: n= 92, s= 2135.70 With excel: =CHIINV(0.025,91) With excel: =CHIINV(0.975,91) 95% confidence interval estimate for standard deviation= = [1865.4102, 2498.3226] Question 2 (A): Perform a hypothesis test for equal population variances in salary for each

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## This note was uploaded on 11/09/2011 for the course BUS ECO 101 taught by Professor Nguyen during the Three '11 term at Monash.

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Assignment 2 - Assignment 2 Question 1 (A): Compute the...

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