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Unformatted text preview: Math 17 TWHFW7 1 st Sem AY 201011 Exercise 1 Part I Answer Key Solutions to Exercise Set I. Please remember that there may be (and proba bly are) multiple ways to go about a given problem. As long as the techniques are valid and the computations are carefully made, you should be able to arrive at the same final answer (or variant form thereof). I. 1. 2 x 4 20 x 3 2 x 2 y 2 z 4 + 16 x 2 yz 2 + 18 = 2 x 2 ( x 2 10 x y 2 z 4 + 8 yz 2 + 9) = 2 x 2 ( x 2 10 x + 25 y 2 z 4 + 8 yz 2 + 9 25 ) = 2 x 2 bracketleftbig( x 2 10 x + 25) ( y 2 x 4 8 yz 2 + 16 )bracketrightbig = 2 x 2 bracketleftBig ( x 5) 2 ( yz 2 4 ) 2 bracketrightBig = 2 x 2 bracketleftbig ( x 5) + ( yz 2 4) bracketrightbig bracketleftbig ( x 5) ( yz 2 4) bracketrightbig = 2 x 2 ( x + yz 2 9)( x yz 2 1) 2. 3( x y ) 2 x + y 2 = 3( x y ) 2 ( x y ) 2 = 3 z 2 z 2 (By letting x y = z .) = (3 z + 2)( z 1) = (3( x y ) + 2) (( x y ) 1) = (3 x 3 y + 2)( x y 1) 3....
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This note was uploaded on 11/09/2011 for the course MATH 17 taught by Professor Aaronjamesporlante during the Summer '11 term at University of the Philippines Diliman.
 Summer '11
 AaronJamesPorlante
 Math, Algebra

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