Lab 1 - Date: To: From: Subject: 8April2010 Dr.MarkZohns...

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Date: 8 April 2010 To: Dr. Mark Zohns From: Roman Ferro Subject: Lab Activity 1 Scotchman Ironworker (Lab 7): A) B) Iron Shear Sum of Moment = FD-24,000lb(d)=0       D=10.75in  d=31.5in                        F = 24000lb(31.5in)/10.75in                        F = 70,326 lb  
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2 1 March 2010 Punch Sum of Moments = FD – 24000lb(d) = 0          D = 23in   d = 31.5in                              F = (24000lb*31.5in)/23in                              F = 32,870lb  Sum of Moments = FD – 32,870lb(d) = 0             D = 30in   d = 5in    F = (32,870lb*30in)/5in                              F = 197,000lb Angle Shear Sum of Moment = FD - 24000lb(d) = 0          D = 5.75in    d = 26.5in                             F = (24000lb*26.5in)/5.75in
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This note was uploaded on 11/14/2011 for the course BRAE 234 taught by Professor Markzohns during the Spring '11 term at Cal Poly.

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Lab 1 - Date: To: From: Subject: 8April2010 Dr.MarkZohns...

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