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lecture16x-hetcor

lecture16x-hetcor - CHEM BCMB 4190/6190/8189 Introductory...

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1 CHEM / BCMB 4190/6190/8189 Introductory NMR Lecture 16 supplement
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2 Lets consider the two-spin AX system ( 13 CHCl 3 ) with A= 1 H = sensitive nuclei and X= 13 C = insensitive nuclei A) At equilibrium: N4 = N N3 = N + ± C N2 = N + ± H N1 = N + ± C + ± H N2 - N4 ± N1 - N3 = ± H N3 - N4 ± N1 - N2 = ± C ± H = 4 * ± C For 13 C spectrum: X1 transition: N3 – N4 = ± C X2 transition: N1 – N2 = ± C X 2 X 1 N2 N1 N3 N4 X1 ²³ ³² ²² ³³ X2 A1 A2
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