c161l09_09_21b

c161l09_09_21b - Calculations with titrations Calculations...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
Calculations with titrations Calculations with titrations W Step 1: Balanced chemical reaction W Step 2: Convert volume of titrant into number of moles W Step 3: Find number of moles of analyte by stoichiometry W Step 4: Find concentration of analyte
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Example Example W Determine the concentration of oxalic acid (H 2 C 2 O 4 ) if 25.00 mL of oxalic acid is titrated against 0.500M NaOH and it took 38.0 mL to reach the equivalence point. Step 1: H 2 C 2 O 4 (aq)+2NaOH(aq) Na 2 C 2 O 4 (aq)+ H 2 O(l) Step 2: 38.0mL×0.500mol/L = 19.0 mmol NaOH used Step 3: 19.0 mmol NaOH × 1 mol H 2 C 2 O 4 /2mol NaOH = 9.5 mmol H 2 C 2 O 4 Step 4: 9.5 mmol H 2 C 2 O 4 / 25.00 mL = 0.380 mol/L
Background image of page 2
Dilution Dilution W Frequently we make one solution from another, more concentrated one. W We need to know how many moles are in the new solution n = MV W The concentration of the new solution is found from the number of moles divided by the new volume M=n/V W M 1 V 1 =M 2 V 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Acidic and Basic Periodic Acidic and Basic Periodic Properties Properties 18 1 2 13 14 15 16 17 Li Be B C N F
Background image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 11

c161l09_09_21b - Calculations with titrations Calculations...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online