Unformatted text preview: random variable. c. Normal Distribution? Not stated, assume it is. d. Large sample? Yes, n = 50 > 30 so CLT may be used. All assumptions seem to be satisfied. 3. Test statistic: Since σ is unknown the test statistic is ( n 1 ) X T ~ t S / n μ= 4. PValue: Given n = 50, X 210 = and S = 18, cal 210 215 T 1.964 18 / 50= = . Because Ha: μ < 215, pvalue = P(T (49) ≤ – 1.96) = 0.025 (approximately) 5. Decision: Assuming α = 0.05, we reject Ho. 6. Conclusion: The observed data indicate that the mean breaking strength of the thread is less than 215 and hence should not be used on the garment (pvalue = 0.025)....
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 Summer '08
 Kyung
 Statistics, Normal Distribution, Standard Deviation, mean breaking strength

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